![Graph the following: \\ a) y = \sqrt {x - 3} \\ b) y = -\sqrt {x - 3} \\ Indicate the domains and ranges for a and b find the intersections. | Homework.Study.com Graph the following: \\ a) y = \sqrt {x - 3} \\ b) y = -\sqrt {x - 3} \\ Indicate the domains and ranges for a and b find the intersections. | Homework.Study.com](https://homework.study.com/cimages/multimages/16/62099221_342109039760216_5531560304040738816_n1693743798087788537.jpg)
Graph the following: \\ a) y = \sqrt {x - 3} \\ b) y = -\sqrt {x - 3} \\ Indicate the domains and ranges for a and b find the intersections. | Homework.Study.com
![functions - How to account for stretching in graph transformation of $y = \ sqrt{x}$? - Mathematics Stack Exchange functions - How to account for stretching in graph transformation of $y = \ sqrt{x}$? - Mathematics Stack Exchange](https://i.stack.imgur.com/smLr1.png)
functions - How to account for stretching in graph transformation of $y = \ sqrt{x}$? - Mathematics Stack Exchange
![calculus - Find the area of the region bounded by the curves $y =\sqrt x$, $ y=x-6$ and the x-axis by integral with respect to x - Mathematics Stack Exchange calculus - Find the area of the region bounded by the curves $y =\sqrt x$, $ y=x-6$ and the x-axis by integral with respect to x - Mathematics Stack Exchange](https://i.stack.imgur.com/Ty2SK.jpg)
calculus - Find the area of the region bounded by the curves $y =\sqrt x$, $ y=x-6$ and the x-axis by integral with respect to x - Mathematics Stack Exchange
SOLUTION: Graph the following function using transformations. Be sure to graph all of the stages on one graph. State the domain and range. y=sqrt(x-3 )+8
![SOLVED: Find the point on the curve y= sqrt(x) that is closest to the point (3, 0). Hint: Rather than minimize the distance between a point (x, y) on the curve and ( SOLVED: Find the point on the curve y= sqrt(x) that is closest to the point (3, 0). Hint: Rather than minimize the distance between a point (x, y) on the curve and (](https://cdn.numerade.com/ask_previews/4edfca44-77b8-4177-ab79-c083eec79416_large.jpg)
SOLVED: Find the point on the curve y= sqrt(x) that is closest to the point (3, 0). Hint: Rather than minimize the distance between a point (x, y) on the curve and (
![How do you find the volume of a rotated region bounded by y=sqrt(x), y=3, the y-axis about the y-axis? | Socratic How do you find the volume of a rotated region bounded by y=sqrt(x), y=3, the y-axis about the y-axis? | Socratic](https://useruploads.socratic.org/GlKwly96QtuRfQrn8GVa_AboutYAxis.gif)