Корень(2)sinx(x-pi/4) +1>0 Нужно решить неравенство. Заранее спасибо. - Школьные Знания.com
=\sin(x-\frac{%CF%80}{4})&line2=\mathrm{Solution:\:}2%CF%80 "f(x)=sin(x-pi/4)")
f(x)=sin(x-pi/4)
=0&line2=\mathrm{Solution\:is\:}x=2%CF%80n%2B\frac{%CF%80}{4},x=%CF%80%2B2%CF%80n%2B\frac{%CF%80}{4} "sin(x-pi/4)=0")
sin(x-pi/4)=0
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